If it's not what You are looking for type in the equation solver your own equation and let us solve it.
16t^2+3t-14=0
a = 16; b = 3; c = -14;
Δ = b2-4ac
Δ = 32-4·16·(-14)
Δ = 905
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{905}}{2*16}=\frac{-3-\sqrt{905}}{32} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{905}}{2*16}=\frac{-3+\sqrt{905}}{32} $
| 24=1/2(b)(6) | | -6(3r+8)=-156 | | 134=2(w+1)+2w | | 30-u=4u | | 3v+4+3=10 | | 7w-17=-4(w-4) | | 9+2(2w-3)=-3(2w-2)+w | | -2(6v-6)+3v=6(v+4) | | 9(m+5)-3(m-2)=8m+30 | | -7a-4=-52 | | -2(6v-6)+3=6(v+4) | | 54=2(w+3)+2w | | 2=-v+264 | | (5x+19)-(6x+5)=180 | | (5x+19)+(6x+5)=180 | | -w+50=211 | | 2x+6/x+3=7 | | 136-v=277 | | -v+283=64 | | (3x+28)+(5x-8)=180 | | -4.905t^2+11t+90=0 | | 4x-1+10x-1=180 | | 185-w=10 | | 5x-16+6x+9=180 | | 3x+29+10x-5=180 | | 6(y+1)=11 | | l=19+1/2+1 | | -4+2/3=2x-5-1x | | -12(-2q+6)+5q=15 | | 18p+15=-6p+15 | | 2(8.95)p=23.65 | | 92=2(w+1)+2w |